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Patch Anticipation Station

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  • sorry :>
    James "2GD" Harding's career as a Dota 2 host on Valve events
    * 25.02.16 - † 26.02.16
    Spoiler: 


    Comment


    • Originally posted by GermanViet View Post
      I did it now.
      If I integrate per parts I get:
      -t^2 * sin(kt)*k + 2t*cos(kt)*k^2 + 2*sin(kt)*k^3

      Since we are integrating from -pi to pi the sinus terms are 0. So we only have the cos term left:
      2t*cos(kt)*k^2

      If I put in the limits (-pi and pi) I get the same result as the professor but my k^2 is a factor, not a divident.

      Is my calculation correct?
      int(cos(kt)dt)=-1/k*sin(kt)

      Comment


      • Originally posted by Physicaque View Post
        int(cos(kt)dt)=-1/k*sin(kt)
        but I'm calculating the integral of t^2 * cos(kt) dt. You are missing t^2.
        James "2GD" Harding's career as a Dota 2 host on Valve events
        * 25.02.16 - † 26.02.16
        Spoiler: 


        Comment


        • Originally posted by GermanViet View Post
          but I'm calculating the integral of t^2 * cos(kt) dt. You are missing t^2.
          I know. You made a mistake in integrating cos(kt). You have to divide by k.

          Comment


          • Honest question:

            Why don't you PM each other?

            Comment


            • They want to show off their mad math skillz
              Spoiler: 
              I guard the rear.

              Comment


              • I don't understand this math

                I think I study these stuff the next semester.

                Comment


                • Originally posted by Noo View Post
                  I don't understand this math

                  I think I study these stuff the next semester.
                  This is usually taught in the last year of high school (at the very end) or in the first year of university.

                  Comment


                  • Originally posted by Physicaque View Post
                    I know. You made a mistake in integrating cos(kt). You have to divide by k.
                    Ohhhhh! I see now. Thanks!
                    James "2GD" Harding's career as a Dota 2 host on Valve events
                    * 25.02.16 - † 26.02.16
                    Spoiler: 


                    Comment


                    • Originally posted by Physicaque View Post
                      int(cos(kt)dt)=-1/k*sin(kt)
                      I think it's a plus, not a minus. Am I wrong?
                      James "2GD" Harding's career as a Dota 2 host on Valve events
                      * 25.02.16 - † 26.02.16
                      Spoiler: 


                      Comment


                      • Originally posted by GermanViet View Post
                        I did it now.
                        If I integrate per parts I get:
                        -t^2 * sin(kt)*k + 2t*cos(kt)*k^2 + 2*sin(kt)*k^3

                        Since we are integrating from -pi to pi the sinus terms are 0. So we only have the cos term left:
                        2t*cos(kt)*k^2

                        If I put in the limits (-pi and pi) I get the same result as the professor but my k^2 is a factor, not a divident.

                        Is my calculation correct?
                        Demonic incantation in PAS! What has become of this place?


                        _____________________________
                        QUARIAN MASTERRACE

                        Comment


                        • I just forgot how to math lol
                          PAS HALL OF FAME
                          Spoiler: 

                          Comment


                          • Originally posted by GermanViet View Post
                            I think it's a plus, not a minus. Am I wrong?
                            Yes. It should be a plus sign.

                            Comment


                            • Originally posted by Physicaque View Post
                              Yes. It should be a plus sign.
                              You are too late. He failed, and now he has to work at mcdonalds forever.

                              Comment


                              • Originally posted by Jimmy81 View Post
                                You are too late. He failed, and now he has to work at mcdonalds forever.
                                What happened to this guy?
                                Spoiler: 

                                Comment

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